Alomerry Wu @ alomerry.com

10. 正则表达式匹配

Sep 13, 2022 · 1min · 195 ·

Description

Difficulty: 困难

Related Topics: Recursion, String, Dynamic Programming

Given an input string s and a pattern p, implement regular expression matching with support for '.' and '*' where:

  • '.' Matches any single character.
  • '*' Matches zero or more of the preceding element.

The matching should cover the entire input string (not partial).

Example 1:

Input: s = "aa", p = "a"
Output: false
Explanation: "a" does not match the entire string "aa".

Example 2:

Input: s = "aa", p = "a*"
Output: true
Explanation: '*' means zero or more of the preceding element, 'a'. Therefore, by repeating 'a' once, it becomes "aa".

Example 3:

Input: s = "ab", p = ".*"
Output: true
Explanation: ".*" means "zero or more (*) of any character (.)".

Constraints:

  • 1 <= s.length <= 20
  • 1 <= p.length <= 20
  • s contains only lowercase English letters.
  • p contains only lowercase English letters, '.', and '*'.
  • It is guaranteed for each appearance of the character '*', there will be a previous valid character to match.

Solution

Language: Go

IOI

 
 comment..
你认为这篇文章怎么样?
  • 0
  • 0
  • 0
  • 0
  • 0
  • 0
  • 0
评论
  • 按正序
  • 按倒序
  • 按热度
Powered by Waline v3.0.1
Theme by antfu
2018 - Present © Alomerry Wu